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Quantum calculator online3/15/2023 ![]() The completion time of A under round robin scheduling with time slice of one time unit is-Ĭlearly, completion time of process A = 9 unit. Their burst CPU time requirements are 4, 1, 8, 1 time units respectively. Average waiting time = (22 + 17 + 23 + 20 + 2 + 12) / 6 = 96 / 6 = 16 unitįour jobs to be executed on a single processor system arrive at time 0 in the order A, B, C, D.If the CPU scheduling policy is Round Robin with time quantum = 3, calculate the average waiting time and average turn around time. If the CPU scheduling policy is Round Robin with time quantum = 2, calculate the average waiting time and average turn around time. Average waiting time = (8 + 8 + 2 + 4 + 7) / 5 = 29 / 5 = 5.8 unitĬonsider the set of 6 processes whose arrival time and burst time are given below.Waiting time = Turn Around time – Burst time.Turn Around time = Exit time – Arrival time.If the CPU scheduling policy is Round Robin with time quantum = 2 unit, calculate the average waiting time and average turn around time. PRACTICE PROBLEMS BASED ON ROUND ROBIN SCHEDULING-Ĭonsider the set of 5 processes whose arrival time and burst time are given below. The value of time quantum should be such that it is neither too big nor too small.The performance of Round Robin scheduling heavily depends on the value of time quantum.When time quantum tends to infinity, Round Robin Scheduling becomes FCFS Scheduling.With increasing value of time quantum, Round Robin Scheduling tends to become FCFS Scheduling.Thus, higher value of time quantum is better in terms of number of context switch. Thus, smaller value of time quantum is better in terms of response time. ![]()
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